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find 2 consecutive integers such that three times the square of the first is equal to seven more than five times the second

User Fza
by
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1 Answer

3 votes

Answer:

Explanation:

We are looking for two numbers,
N and
N + 1. From the problem statement, we can setup the following equation:


3N^(2) = 5(N + 1) + 7


3N^(2) = 5N + 5 + 7


3N^(2) - 5N - 12 = 0


(3N + 4)(N - 3)


N = (-4)/(3), 3

Because 3 is the only integer solution, the answer is 3 and 4.

User Martin Smith
by
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