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Which system of linear inequalities is shown in the graph

Which system of linear inequalities is shown in the graph-example-1

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Answer:

The answer to your question is:

x + 2y - 4 ≥ 0 and 2x -y -3 > 0

Explanation:

First look for two points of each line to fine the line equations

1 st line points: (2, 1) ; (0, 2)

2nd line points: (2, 1) ; (3, 3)

1st line slope

m = (2 - 1) / (0 - 2) = 1 / -2 = -1/2

2nd line slope

m = (3 - 1) / ( 3 - 2) = 2 / 1 = 2

1st line

y - 1 = -1/2 (x - 2)

2y - 2 = -1(x - 2)

2y - 2 = -x + 2

x + 2y - 4 = 0 Inequality x + 2y - 4 ≥ 0

2nd line

y - 1 = 2(x - 2)

y - 1 = 2x - 4

2x -y -3 = 0 Inequality 2x -y -3 > 0

User Ferdinando Randisi
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