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3) When the temperature of a blackbody increases from 900 K to 2300 K, by what factor does the total power of the electromagnetic radiation per-unit- area increase?

User Mguimard
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1 Answer

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Answer:

The electromagnetic radiation per-unit- area increase by 42.65 times.

Step-by-step explanation:

The radiation per-unit- area (P) is directly proportional to the fourth power of the temperature. Thus,

P ∝ T⁴

For, when the temperature is raised from T₀ to T₁ , the radiation per-unit- area is related to as:


\frac {P_1}{P_0}=\frac {T_1^4}{T_0^4}

T₀ = 900 K

T₁ = 2300 K


\frac {P_1}{P_0}=\frac {2300^4}{900^4}

So,

P₁ = 42.65 P₀

The electromagnetic radiation per-unit- area increase by 42.65 times.

User Darius Jahandarie
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