Question

A charge Q = 1.96 10-8 C is surrounded by an equipotential surface with a surface area of 1.18 m2. what is the electric potential at this surface?

Answer 1

V = 575.6 Volts

Step-by-step explanation:

As we know that surface area of the equi-potential surface is given as

`A = 1.18 m^2`

so we will say

`A = 4\pi r^2`

`1.18 = 4\pi r^2`

`r = 0.31 m`

Now the potential due to a point charge is given as

`V = (kQ)/(r)`

`V = ((9* 10^9)(1.96 * 10^(-8)))/(0.31)`

`V = 575.6 Volts`