Question

A football is kicked from ground level at an angle of 53 degrees. It reaches a maximum height of 7.8 meters before returning to the ground. How long will the football spend in the air, in seconds?

Answer 1

1.61 second

Step-by-step explanation:

Angle of projection, θ = 53°

maximum height, H = 7.8 m

Let T be the time taken by the ball to travel into air. It is called time of flight.

Let u be the velocity of projection.

The formula for maximum height is given by

`H = (u^(2)Sin^(2)\theta )/(2g)`

By substituting the values, we get

`7.8= (u^(2)Sin^(2)53 )/(2* 9.8)`

u = 9.88 m/s

Use the formula for time of flight

`T = (2uSin\theta )/(g)`

`T = (2* 9.88* Sin53 )/(9.8)`

T = 1.61 second