Question

Pd).
cot x/sec x
show that -=cos ecx -sin x
​

Answer 1

see explanation

Explanation:

Using the trigonometric identities

• cot x =
`(cosx)/(sinx)`

• sec x =
`(1)/(cosx)` and cosec x =
`(1)/(sinx)`

Consider the left side

`(cotx)/(secx)`

=
`(cosx)/(sinx)` × cosx

=
`(cos^2x)/(sinx)`

=
`(1-sin^2x)/(sinx)`

=
`(1)/(sinx)` -
`(sin^2x)/(sinx)`

= cosec x - sin x

= right side ⇒ verified