Question

How many moles of solute particles are present in 7.94 mL of 0.887 M NaNO3? When you have your answer, take the LOG (base 10) of your answer and enter it with 2 decimal places.

Answer 1

To calculate the number of moles of solute particles in a solution, multiply the molarity by the volume of the solution. In this case, the result is 0.0070 mol. Taking the LOG (base 10) of the result gives -2.15.

Step-by-step explanation:

To determine the number of moles of solute particles in a solution, you need to consider the molarity and volume of the solution. In this case, the molarity is 0.887 M and the volume is 7.94 mL. To calculate the number of moles, you can use the formula:

Moles = Molarity x Volume

Converting mL to L:

7.94 mL = 7.94/1000 L = 0.00794 L

Now, substitute the values into the formula:

Moles = 0.887 M x 0.00794 L = 0.0070 mol

Taking the LOG (base 10) of 0.0070, we get -2.15 (rounded to 2 decimal places).

Answer 2

The answer is 7.04278 x 10⁻³, and the log(10) is -2.15

Step-by-step explanation:

In a 0.887 M NaNO₃ solution there are 0.887 mol in 1 liter of solution, We know that 1 L= 1000 ml, so we can calculate the number of mol which are in 7.94 ml as follows:

solute mol= 7.94 ml x 0.887 mol/ 1000 ml = 7.04278 x 10⁻³ mol

We take log(10) of 7.04278 x 10⁻³ and we obtain: -2.15