Answer:
Acceleration of the bullet while moving into the clay is -312500 ms⁻²
Step-by-step explanation:
Given data
Initial velocity (v₁) = 250 m/s Final velocity (v₂) = 0 m/s
Distance (s)= 0.1 m acceleration (a) = ?
Using 3rd equation of motion
2as = v₂²- v₁²
2 × a × 0.1 = 0² - 250²
0.2 × a = -62500
a = -62500/0.2
a = -312500 m/s²
Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.