Question

What is the equation for the line which contains the point (-2,-11) and has slope 5?

pls answer

Answer 1

Step-by-step explanation: y = 5x - 1

y = mx + c

slope = m = 5

-> y = 5x + c

input the point into the equation to find c:

(-2, -11) -> there's a point on this line that passes through x= -2 and y = -11

so we input these into the equation:

-11 = 5*(-2) + c

-11 = -10 + c

c = -1

-> eqn is y = 5x - 1