Answer:
The value of standard deviation is 3.894 minutes.
Explanation:
Consider the provided table:
Complete the table as shown:
Length of time f class mid pt(x) f·x x² f·x²
1-4 4 2.5 10 6.25 25
4-7 8 5.5 44 30.25 242
7-10 14 8.5 119 72.25 1011.5
10-13 9 11.5 103.5 132.25 1190.25
13-16 5 14.5 72.5 210.25 1051.25
16-19 2 17.5 35 306.25 612.5
n=42 ∑f·x=384 ∑f·x²=4132.5
Now use the formula to calculate standard deviation.
![s=\sqrt{(n[\sum(f\cdot x^2)]-[\sum(f\cdot x)]^2)/(n(n-1))}](https://img.qammunity.org/2020/formulas/mathematics/college/6qm3ulj08krlvn8kb9xmygrt96530q3djo.png)
Substitute the respective values in the above formula and solve for s.


Hence, the value of standard deviation is 3.894 minutes.