Answer:
distance of 2nd team from 1st team will be: 58.2
Direction of 2nd team from 1st team will be: 14.90 deg North of east
Step-by-step explanation:
ASSUME Vector is R and makes angle A with +x-axis,
therefore component of vector R is


From above relation
Assuming base camp as the origin, location of 1st team is
away at 21 deg North of west (North of west is in 2nd quadrant, So x is -ve and y is positive)


location of 2nd team is at
, at 38 deg East of North = 32 km, at 58 deg North of east (North of east is in 1st quadrant, So x and y both are +ve)


Now position of 2nd team with respect to 1st team will be given by:


Using above values:


distance of 2nd team from 1st team will be:


Direction of 2nd team from 1st team will be:
![Direction = tan^(-1) (R_(3y))/(R_(3x)) = tan^(-1)[ (13.71)/(51.49)]](https://img.qammunity.org/2020/formulas/physics/high-school/smb62p8kv3yasw3nnsercfj7oaierbkpd8.png)
Direction = 14.90 deg North of east