Question

Solve the equation 3(2^2x +3) - 5(2^2x+2) - 156 = 0 leaving your answer in logarithmic form​

Answer 1

Hello,

Explanation:

`3*2^(2x+3)-5*2^(2x+2)-156=0\\\\6*2^(2x+2)-5*2^(2x+2)=156\\\\2^(2x+2)=156\\\\(2x+2)*ln(2)=ln(156)\ (naturel\ logarithm)\\\\2x+2=(ln(156))/(ln(2)) \\\\x=((ln(156))/(ln(2)) -2)/(2) \\\\x=(ln(156))/(ln(4))-1 \\x\approx{2,64270...}`