Question

He point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?

x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2

Answer 1

a

Explanation:

Answer 2

`x-4y=8`

Explanation:

we have

`y-1=(1)/(4)(x-12)`

Convert to standard form

`Ax+By=C`

where

A is a positive integer

B and C are integers

Multiply by 4 both sides to remove the fraction

`4y-4=x-12`

subtract 4y both sides

`-4=x-12-4y`

Adds 12 both sides

`-4+12=x-4y`

`8=x-4y`

Rewrite

`x-4y=8`