Question

Which equation represents a line that passes through 4 1/3 and has a slope of 3/4

A. y-3/4 = 1/3 (x-4)
B. y-1/3 = 3/4 (x-4)
C. y-1/3 = 4 (x-3/4)
D. y-4 =3/4 (x-1/3)

Answer 1

B.
`y - (1)/(3) = (3)/(4)(x - 4)`

Explanation:

The point-slope form of the equation of a line is

`y - y_1 = m(x - x_1)`

where m = slope, and
`(x_1, y_1)` is a point on the line.

In your case,

m = 3/4,
`x_1 = 4`, and
`y_1 = (1)/(3)`

Substitute the values just above into the equation to get

`y - (1)/(3) = (3)/(4)(x - 4)`

The answer is B.
`y - (1)/(3) = (3)/(4)(x - 4)`

Answer 2

B

Explanation:

equation of a line =

y-y1=m(x-x1)

where m is the gradient and X1 and y1 are the points on the line.

slope= gradient

4=X, 1/3= y

y-1/3 = 3/4 (x-4)