Answer:
The answer to your question is: Perimeter = 108 in
Explanation:
Data
Length (l) = 5 width (w)
A = 405 in²
Perimeter = ?
Formula
Area = l x w
Perimeter = 2w + 2l
Process
405 = 5w x w
405 = 5w²
405/5 = w²
w = √81
w = 9 in
l = 5(9) = 45 in
Perimeter = 2(9) + 2(45)
= 18 + 90
= 108 in