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A chemical process requires 7.300 g-mol of calcium sulfate (CaSO.) for a reaction. How many grams are in 7.300 g-mol of calcium sulfate? Caso

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Answer: The mass of copper sulfate is 1165 grams.

Step-by-step explanation:

We are given:

Number of gram-moles of copper sulfate = 7.300 g-mol

We know that:

1 g-mol = 1 mol

So, number of moles of copper sulfate = 7.300 mol

To calculate the number of moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of copper sulfate = 159.6 g/mol

Moles of copper sulfate = 7.300 moles

Putting values in above equation, we get:


7.300mol=\frac{\text{Mass of copper sulfate}}{159.6g/mol}\\\\\text{Mass of copper sulfate}=1165g

Hence, the mass of copper sulfate is 1165 grams.

User Timo Jokinen
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