Question

Measurement of heat conductivity A metal panel of area A = 100 cm² and thickness Y = 0.5 cm was found to conduct heat at a rate of 3 W at steady state with temperatures To = 25 °C and T, = 30 °C imposed on the two main surfaces. What is the average thermal conductivity of the material at this temperature range?

Answer 1

The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.

Step-by-step explanation:

The heat flow through this area of the metal panel can be expressed as:

`q/A=-k((T_2-T_1))/(Y)`

being A the surface area, k the thermal conductivity, T2 and T1 the temperatures in each side and Y the thickness of the metal panel.

We have to rearrange the equation to clear k:

`k=(-(q/A)*Y)/(\Delta T) = (-(3 W/100 cm2)*0.5cm)/(5 ^\circ K)*((1m)/(100cm) )^(3) \\\\k=(0.015)/(5*100^(3) )W/mK= 3*10^(-9)W/mK`

The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.