Question

What is the gauge pressure exerted by sea-wo bottom of a pool that is 2.5 m deep, 12.0 m wide and 30.0 m long

Answer 1

Step-by-step explanation:

Relation between gauge pressure and density and height is as follows.

`P_(gauge) = \rho * g * h`

The given data is as follows.

`\rho` = 1025
`kg/m^(3)`

g = 9.81
`m/s^(2)`

h = 2.5 m

Therefore, substitute the given values into the above formula as follows.

`P_(gauge) = \rho * g * h`

=
`1025 kg/m^(3) * 9.81 m/s^(2) * 2.5 m`

=
`25138.125 N/m^(2)`

or, =
`25.138125 kN/m^(2)`

= 25.138125 kPa

Thus, we can conclude that the gauge pressure exerted by sea-water is 25.138125 kPa.