Answer : The amount of work this pump can do in kJ/kg is,
![4.2kJkg^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/i4e2i2xl0ofohplruhvk61zhvzsuxlo1r9.png)
Explanation :
Conversion used :
![1kPacm^3=1000Pacm^3](https://img.qammunity.org/2020/formulas/chemistry/college/j49gyt5bgixexh0adk5ges7ytb8mmkomc9.png)
![1000Pacm^3=1000Pa* 10^(-6)m^3=10^(-3)Pam^3](https://img.qammunity.org/2020/formulas/chemistry/college/8dq1688knj0o36aa9x1wfdjnj0av4ng7a3.png)
And,
![1Pam^3=1J](https://img.qammunity.org/2020/formulas/chemistry/college/g8oi4gnlp7ir056x0c9j4tj1t18wxefsax.png)
So,
![10^(-3)Pam^3=10^(-3)J](https://img.qammunity.org/2020/formulas/chemistry/college/14gxnjxre781ozo44gfvjryzra3xrtk2gl.png)
or,
![10^(-3)Pam^3kg^(-1)=10^(-3)Jkg^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/cx3s73tmdnultfixa4k3ylx1khqhns5eqi.png)
so,
![1kPacm^3kg^(-1)=10^(-3)* 10^(-3)kJkg^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/1eaphpc9xed3wgaubvpm0fefw31v0qdtcu.png)
As we are given that,
work of pump =
![4.2* 10^6kPacm^3kg^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/p3f71raw35ocul9ropu9vo3x7bxjt8k6ei.png)
So, the work of pump in kJ/kg is:
work of pump =
![4.2* 10^6kPacm^3kg^(-1)(10^(-3)* 10^(-3)kJkg^(-1))/(1kPacm^3kg^(-1))](https://img.qammunity.org/2020/formulas/chemistry/college/75mpnqq36q92govc8fox8eqj8hj7wvx0tw.png)
work of pump =
![4.2kJkg^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/i4e2i2xl0ofohplruhvk61zhvzsuxlo1r9.png)
Therefore, the amount of work this pump can do in kJ/kg is,
![4.2kJkg^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/i4e2i2xl0ofohplruhvk61zhvzsuxlo1r9.png)