Answer:
3.0857 moles of air
Step-by-step explanation:
For this situation, we will use the ideal gas wet: PV = nRT
⇒ with P = pressure (in atm)
⇒ with V = volume (in liter)
⇒ with n = number of moles of gas
⇒ with R = the ideal gas constant = 0.0821 L * atm * K^-1 * mol^-1
⇒ with T = the absolute temperature (in Kelvin)
⇒ 915 °C = 915 + 273.15 K = 1188.15 K
To calculate the number of moles of air we have to distort the formule:
n= (P*V) / (R*T) = (1.075 atm * 280 L) / ( 0.0821 L * atm * K^-1 * mol^-1 * 1188.15 K)
n = 3.0857 moles of air