Question

Calculate the grams of solid product and excess reagent when 2.50 grams of barium chloride is mixed with 4.00 grams of magnesium sulfate. Calculate the grams of solid product when 2.50 grams of calcium chloride is mixed with excess potassium carbonate

Answer 1

2.56gMgSO4 in excess

mBaSO4 = 2.8gBaSO4

mCaCO3 = 2.25gCaCO3

Step-by-step explanation:

Hello! To know which is the limiting reagent, which is the one I will use to calculate the product, I have to see how much reagent I use of each one and see if I have it or not.

mBaCl2 = 4gMgSO4 * (208gBaCl2 / mol / 120gMgSO4 / mol) = 6.93gBaCl2 (I don't have it so it is the limiting reagent

mMgSO4 = 2.5gBaCl2 * (120gMgSO4 / mol / 208gBaCl2 / mol) = 1.44g

MgSO4 excess reagent

Since I have 4g and use only 1.44, the total of the remaining reagent is (4-1.44) g = 2.56gMgSO4 in excess

To calculate the product

mBaSO4 = 2.5gBaCl2 * (233gBaSO4 / mol / 208gBaCl2 / mol)

mBaSO4 = 2.8gBaSO4

To calculate the amount of product I can get with calcium chloride

mCaCO3 = 2.5gCaCl3 * (100gCaCO3 / mol / 111gCaCl2 / mol)

mCaCO3 = 2.25gCaCO3