Question

A package is dropped from a helicopter falling at 36 m/s.

If it takes 11.0s before the package strikes the ground, how high above the ground was the package when it was released? Ignore air resistance

Answer 1

396 meters. because if the package is falling at 36m/s then, we just have to multiply 36×11 and we get our height which is 396 meters bb:)

Answer 2

The height above the ground is 988.9 meters.

Step-by-step explanation:

It is given that,

Initial speed of the package, u = 36 m/s

Time taken by the package to reach the ground, t = 11 s

Let h is the height above the ground when it was released. It can be calculated using the second equation of motion as :

`h=ut+(1)/(2)at^2`

a = g

`h=ut+(1)/(2)gt^2`

`h=36* 11+(1)/(2)* 9.8* 11^2`

h = 988.9 meters

So, the height above the ground is 988.9 meters. Hence, this is the required solution.