Question

What is the volume in mL of a 2.48 M Nal solution that contains 63.5 grams of Nal? (1.1 mL) 1.4.c

Answer 1

The volume of NaI is 170.8 mL

Solution:

As per the question:

Mass of NaI = 63.5 g

Molarity of NaI solution = 2.48 M

Now,

We know that molar mass of NaI = 149.89 g/mol

To calculate the moles of NaI, we use:

`Moles = (Mass\ of\ NaI)/(Molarity)`

`Moles = (63.5)/(149.89) = 0.424`

Also,

Molarity =
`(Moles)/(Volume\ of\ NaI)`

Volume of NaI =
`(0.424)/(2.48) = 0.1708 L = 170.8 mL`