Question

A trinomial with a leading coefficient of 3 and a constant of -5

Answer 1

`3x^2+x-5`

Explanation:

So let's figure out our definitions here:

A trinomial is a function that looks like this:
`x^2+x+1`

A leading coefficient is the number before the variable with the highest value. In this case, it would be the number before
`x^2`, making this function now
`3x^2+x+1`.

A constant is a number that doesn't change no matter what the variable is, which would be that last number,
`1`. Therefore, our function is now
`3x^2+x-5`, which is our answer.

Answer 2

Answer: 3*x^2 + b*x - 5

Explanation:

We know that a trinomial equation has the shape of:

a*x^2 + b*x + c

Where the leading coefficient is a, and the constant is c

So we have a = 3, c = -5

so the trinomial that we are looking for is:

3*x^2 + b*x - 5

Where the value of b can be any real number.