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5 votes
Consider the series given below.

2, 6, 18, 54, ...
Given that the sum of the first n terms of the provided series is 6,560, determine the value of n.​

User TTimo
by
5.3k points

2 Answers

2 votes

Answer:

8

Explanation:

User Magic Bean
by
7.0k points
4 votes

Answer:

n = 8

Explanation:

This is a geometric sequence where the sum to n terms is


S_(n) =
(a(r^n-1))/(r-1)

where a is the first term and r the common ratio

r = 6 ÷ 2 = 18 ÷ 6 = 54 ÷ 18 = 3 and a = 2, thus


(2(3^n-1))/(3-1) = 6560


(2(3^n-1))/(2) = 6560 ← cancel the 2


3^(n) - 1 = 6560 (add 1 to both sides )


3^(n) = 6561

note that 6561 =
3^(8), hence


3^(n) =
3^(8) ⇒ n = 8

User Harald Thomson
by
6.1k points