Answer:
The answer is C
Explanation:
3x^{3}+x^{2}-10x:0 this is the original equation and you make it equal to 0
x(3x^{2} +x-10):0 you take the x as a common variable
x:0 (3x^{2} +x-10):0 you have that x:0 and the other equation that you have to break in two parenthesis as following :
(3x-5) (x+2):0 then, each one of the parenthesis equals cero
3x-5:0 3x:5 x:5/3 \\x-2:0 x:2\\