Question

An academic department has just completed voting by secret ballot for a departmenthead. The ballot box contains four slips with votes for candidate A and three slips with votes for candidate B. Suppose these slips are removed from the box one by one, What isthe total number of possible outcomes?

Answer 1

Answer: 35

Explanation:

Given : An academic department has just completed voting by secret ballot for a department head.

The ballot box contains 4 slips with votes for candidate A and 3 slips with votes for candidate B.

Total slips = 7

The permutations of 'n' things from which 'a' things are like , 'b' things are like is given by :-

`(n!)/(a!\ b!)`

Now, the total number of possible outcomes for the given situation will be:

`(7!)/(4!\ 3!)=(7*6*5*4!)/(3*2*1*\ 4!)\\\\=35`

Hence, the total number of possible outcomes =35