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A floral shop receives a $480 order for roses and carnations. The order contains twice as many roses as carnations. The prices per dozen for the roses and carnations are $23 and $34, respectively. How many, in dozens, of each type of flower are in the order?

1 Answer

2 votes

Answer:

12 dozens roses, 6 dozens carnations

Explanation:

Let r be every dozen roses and c every dozen carnations.

Then, the price for
r_(n) dozens roses will be 23r and the price for
c_(n) dozens carnations will be 34c.

So the price for the total of roses and carnations together will be 480:


23r+34c=480 (1)

"twice as many roses as carnations" means that if we multiply the quantity of dozens carnations by 2, it will be equal the quantity of dozens roses.


r=2c (2)

then we substitute (2) in (1) as follows:


23(2c)+34c=480\\46c+34c=480\\80c=480\\c=6

If c=6, then r=12 for (2).

Where c and r are the dozens of each flower.

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