Answer:
see below for a graph
Explanation:
The first inequality does not include the "equal to" case, so its boundary is graphed with a dashed line. If we consider only the y term, we have y < ..., so the shading is below the line.
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The second inequality includes the "equal to" case, so its boundary line is solid. Again, considering only the y-term, we have y ≥ ..., so the shading is above the line.
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We find that points (-6, 0) and (0, 6) will satisfy both inequalities, as will any point in the doubly-shaded area.