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I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI 2CuI+4KCl+I2

User Anjayluh
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1 Answer

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Answer:

React with 0.847 mol of KI

Produce:

0.4235 mol of CuI

0.847 mol of KCl

0.21175 moles de I2

Step-by-step explanation:

2CuCl2 + 4KI produce 2CuI + 4KCl + I2

The stoichiometric coefficients give us the relationship in moles:

2 mol of CuCl2 ....react whit....4 mol of KI

0.4235 mol of CuCl2 ....react whit...X= 0.847mol of KI

2 mol of CuCl2 ....produce....2 mol of CuI

0.4235 mol of CuCl2 ....produce....X=0.4235 mol of CuI

2 mol of CuCl2 ....produce....4 mol of KCl

0.4235 mol of CuCl2 ....produce....X= 0.847 mol of KCl

2 mol of CuCl2 ....produce.... 1 mol of I2

0.4235 mol of CuCl2 ....produce....X= 0.21175 moles de I2

If you need to know the mass that is produced you just have to multiply the moles by the molecular mass

User Chris Van Opstal
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