Answer:
The answer to your question is: three hours.
Explanation:
data
Jogger 1 = 6 mi/h
Jogger 2 = 6.5 miles/h , starts 15 min (0.25 h) after the first Jogger
Time when the second jogger catch the first jogger = ?
Process
Advantage of the first jogger d = vt = 6(0.25) = 1.5 mi
Distance where they meet 1.5 + 6t = 6.5t
Find the t value 6.5t - 6t = 1.5
0.5 t = 1.5
t = 1.5 / 0.5
t = 3 hours