Question

If a drag racer wins the final round of her race by going an average speed of 198.37 miles per hour in 4.537 seconds, what distance did he cover?

Answer 1

The distance covered by drag racer by going an average speed of 198.37 miles per hour in 4.537 seconds is 0.2500 miles.

Solution:

By using the relationship between distance speed and time, distance is the product of speed and time.

`\begin{array}{l}{\text {Speed}=\frac{\text {Distance}}{\text {Time}}} \\\\ {\text {Distance}=\text {Speed} * \text {Time}}\end{array}`

Converting seconds to hours,

We know that
`1 \text { second }=(1)/(3600) \text { hours }`

So,
`4.537 \text { seconds }=4.537 * (1)/(3600) \text { hours }`

Average speed = 198.37 miles per hour and time =
`4.537 * (1)/(3600) h o u r s`

`\begin{array}{l}{\text {Distance}=198.37 \frac{\text { miles }}{\text { hours }} * 4.537 * (1)/(3600) \text { hours }} \\\\ {\text { Distance }=198.37 * 4.537 * (1)/(3600) \text { miles }=198.37 * 0.00126} \\\\ {\Rightarrow 0.250001 \approx 0.2500}\end{array}`

Distance = 0.2500 miles