Question

A uniform charge density of 500 nC/m3 is distributed throughout a spherical volume (radius = 16 cm). Consider a cubical (4.0 cm along the edge) surface completely inside the sphere. Determine the electric flux through this surface.

a. 7.1 N m²/C
b. 3.6 N m²/C
c. 12 N m²/C
d. 19 N m²/C
e. 970 N...

Answer 1

=3.62 N m^2 / C

Step-by-step explanation:

We know that electric flux φ

φ = Q / ε0 where Q is the"enclosed" charge - Gauss' Law

ε_0= constant

also,

φ = ρ V / ε0

ρ and V are density and volume and their product give charge density.

=
`(500*10^(-7)0.04^3)/(8.85*10^(-12))`

calculating we get

φ = 3.62 N m^2 / C

therefore, electric flux through this surface = 3.62 N m^2 / C