Question

You go to a water fountain and note that the trajectoryy of the water coming from the nozzle has a range of 6 centimeters at level range. You estimate that the angle that the water makes coming out of the nozzle is 70 degrees. What is the speed of the water?

Answer 1

speed of water coming out of the nozzle is 0.96 m/s

Step-by-step explanation:

range of the water coming from nozzle has range 6 cm

now we know that the angle through which it started is 70 degree

now we know that

`Range = (v^2sin(2\theta))/(g)`

now plug in all data

`0.06 = (v^2 sin140)/(9.81)`

`v = 0.96 m/s`

So the water jet will come out from the nozzle with speed 0.96 m/s