Question

An HR director numbered employees 1 through 50 for an extra vacation day contest. What is the probability that the HR director will select an employee who is not a multiple of 13?

Give your answer as a fraction.​

Answer 1

The probability that the HR director will select an employee who is not a multiple of 13 is
`(47)/(50)`

Explanation:

* Lets explain how to solve the problem

- The probability of an event is the measure of the chance that the

event will occur

- The probability of an event A is the number of ways that event A can

occur divided by the total number of possible outcomes

- If P(A) is the probability of event A, is the probability that the event A

does not occur is 1 - P(A)

* Lets solve the problem

- An HR director numbered employees 1 through 50 for an extra

vacation day contest

∴ There are 50 employees

- The HR director will select an employee

- We need to find the probability of select an employees who is not

multiple of 13

* At first lets find the multiples of 13

∵ 13 × 1 = 13

∵ 13 × 2 = 26

∵ 13 × 3 = 39

∴ The multiples of 13 from 1 to 50 are 13 , 26 , 39

∵ There are 3 multiples of 13

∵ There are 50 numbers

∵ Probability of multiple of 13 =
`(3)/(50)`

∵ Probability of not multiple of 13 = 1 - P(multiple of 13)

∴ Probability of not multiple of 13 =
`1-(3)/(50)`

∴ Probability of not multiple of 13 =
`(47)/(50)`

* The probability that the HR director will select an employee who is

not a multiple of 13 is
`(47)/(50)`