Question

Use the References to access important values if needed for this question. The radius of a potassium atom is 231 pm. How many potassium atoms would have to be laid side by side to span a distance of 2.91 mm? atoms Submit Answer Try Another Version 1 item attempt remaining

Answer 1

6298702 potassium atoms would have to be laid side by side to span a distance of 2,91 mm

Step-by-step explanation:

If the radius of a potassium atom is 231 pm, then the diameter would be:

d = 2r = 2*(231) = 462 pm

So each potassium atom occupies a space of 462 pm, we can express this relationship as follows:

`(1 potassium atom)/(462 pm)`

To solve this problem, we'll use the following conversion factors:

1 pm = 1×E−12 m

1000 mm = 1 m

We begin to accommodate all our relationships starting from that numerical expression that is not written as a relationship (usually the one in the question), and in such a way that the units are eliminated between them.

`2, 91 mm * (1 m)/(1000 mm)*( 1 pm)/(1*10^(-12)m )*(1 potassium atom)/(462 pm)= 6298701.3` potassium atoms

So, we'll need 6298702 potassium atoms to span a distance of 2,91 mm