Answer:
1.) Incorrect,
2.) Correct
Explanation:
1.) Let x be the amount of money,
After increasing x by 20%,
New amount of money ( say y )= (100+20)% of x ( i.e. y is 20% more than x )
= 120 % of x
![=(120x)/(100)](https://img.qammunity.org/2020/formulas/mathematics/college/4khrrg7or7lr20ge8f7z6ge9qkejx0u5js.png)
⇒ y = 1.20x
![\because (y-x)/(y)* 100=( 1.20x-x)/(1.20x)* 100](https://img.qammunity.org/2020/formulas/mathematics/college/kr0iys0xuzzv3e4itht21ouusfx7nqm291.png)
![=(0.2x)/(1.2x)* 100](https://img.qammunity.org/2020/formulas/mathematics/college/k7pdq6kd94wysg82rsky0pzva9csberl1e.png)
![=(20)/(1.2)](https://img.qammunity.org/2020/formulas/mathematics/college/dkxbpzmro5bwagr4vsns7a4damag5icib8.png)
≈ 16.67%
Thus, x is approximately 16.67% less than y.
2.) First score = 60%,
Second score = x% ( let )
So, Average percentage score =
![(60+x)/(2)](https://img.qammunity.org/2020/formulas/mathematics/college/vs881c13fwgd5o8mvtojf0qrtdsns23rt3.png)
If
![(60+x)/(2)=70](https://img.qammunity.org/2020/formulas/mathematics/college/7t8793l6seie3h1hvtacqt2qup4tnc6kuy.png)
![60+x=140\implies x = 80](https://img.qammunity.org/2020/formulas/mathematics/college/vblnxqwz5ib1cg7rns6knryecwapgrd9sl.png)