Question

How many liters of 0.1107 M KCI contain 15.00 g of KCI (FW 74.6 g/mol)? 0.02227 L O 0.5502 L 1.661 L O 1816 L 18.16 L ent Navigator PrtScr Delete FB F9 F10 F11 F12 Insert Backspace 6 U P

Answer 1

To determine the volume of 0.1107 M KCl solution containing 15.00 g of KCl, we can use the formula Molarity (M) = moles of solute / volume of solution (in liters). By calculating the moles of KCl and using the molarity formula, the volume of the solution is found to be 1.814 L.

Step-by-step explanation:

To calculate the number of liters of 0.1107 M KCl that contain 15.00 g of KCl, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we need to calculate the moles of KCl using its molecular weight:

Moles of KCl = mass of KCl / molecular weight of KCl

Moles of KCl = 15.00 g / 74.6 g/mol = 0.201 moles of KCl

Now, we can use the formula to calculate the volume of solution:

Volume of solution = moles of solute / molarity

Volume of solution = 0.201 moles / 0.1107 M = 1.814 L

Answer 2

Answer: The volume of solution required is 1.816 L

Step-by-step explanation:

To calculate the molarity of solution, we use the equation:

`\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}* \text{Volume of solution (in L)}}`

We are given:

Mass of solute (KCl) = 15.00 g

Molar mass of potassium chloride = 74.6 g/mol

Molarity of solution = 0.1107 M

Putting values in above equation, we get:

`0.1107M=\frac{15.00g}{74.6g/mol* \text{Volume of solution}}\\\\\text{Volume of solution}=1.82L`

Hence, the volume of solution required is 1.816 L