1 Answer

NestorArturo · Answer 1 · 2020-12-22T12:09:14+0000

Answer:

$(Wm^2C^(\circ))/(m^2-C^(\circ))$

Explanation:

We are given that A=
$(W)/(m^2-C^(\circ))$

B=
m^2

C=
$C^(\circ)$

We are given that
D=A* B* C

We have to find the unit if D

Substitute the values then we get

$D=(W)/(m^2-C^(\circ))* m^2* C^(\circ)=(Wm^2C^(\circ))/(m^2-C^(\circ))$

$D=(Wm^2C^(\circ))/(m^2-C^(\circ))$

Hence, units of D=
$(Wm^2C^(\circ))/(m^2-C^(\circ))$

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