Question

A life preserver is thrown from an helicopter straight down to a person in distress. The initial velocity of the life preserver is 1.60 m/s and it takes 2.3 s to reach the water. (a) List the knowns in this problem. (b) How high above the water was the preserver released? Note Ignore air resistance.

Answer 1

Answer:29.627 m

Step-by-step explanation:

Given

Initial velocity of life preserver(u) is 1.6 m/s

it takes 2.3 s to reach the water

using equation of motion

v=u+at

`v=1.6+9.81* 2.3`

v=24.163 m/s

Let s be the height of life preserver

`v^2-u^2=2gs`

`24.163^2-1.6^2=2* 9.81* s`

`s=(581.29)/(2* 9.81)`

s=29.627 m