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If f(x)=7/x^2, then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x=3 and x=4

1 Answer

3 votes

Answer:


Area=(7)/(12)

Explanation:


Area=\int\limits^a_b {f(x)} \, dx =\int\limits^4_3 {(7)/(x^(2)) } \, dx =-7*(1)/(x)=-7(1/4-1/3)=(7)/(12)

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