Question

A baseball goes from zero to 34 m/s in 0.188 s. What is its average acceleration? Answer in units of m/s^2

Answer 1

`a_(avg) = 180.85 m/s^(2)`

Given:

Initial velocity, u = 0 m/s

Final velocity, v = 34 m/s

Time interval,
`\Delta t = 0.188 s`

Solution:

Acceleration is the rate at which the velocity of an object changes.

Thus

Average acceleration,
`a_(avg) = (\Delta v)/(\Delta t)`

`a_(avg) = (v - u)/(t - 0) = (34 - 0)/(0.188) = 180.85 m/s^(2)`