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two automobiles leave a city at the same time and travel along straight highways that differ in direction by 84 degrees. if their speeds are 60 mi/hr and 45 mi/hr, approximatly how far apart are the cars at the end of 20 minutes?

1 Answer

4 votes

Answer:

D = 23.7 miles

Explanation:

Given data:


\theta=84 degrees

Time
= 20 min = (1)/(3) hr

Distance of A
= (60 mi/hr)* (1)/(3) hr =20 mi

Distance of B =
(45 mi/hr)(1)/(3) hr = 15 mi

Draw a triangle.

By using cosine formula we can determine the distance between them


D^2 = 20^2 + 15^2 - 2* 20* 15* cos(84)


D^2 = 625 - 600 cos(84)


D^2 = 625 - 63.2


D^2 = 561.8

Thus D = 23.7 miles

two automobiles leave a city at the same time and travel along straight highways that-example-1
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