Question

You're a newly appointed Engineer in APE Chemical Sdn Bhd. and your first task is to design a 0.35m vessel to be used to store saturated vapor ethanol at 480°C and 6000 kPa. For these conditions, analyze (6) The molar volume of the saturated vapor ethanol. . (15 marks) (6) The mass of the saturated vapor ethanol in the vessel

Answer 1

molar volume of vapor ethanol is
`V = 1.043 * 10^(-3) m^3/mol`

mass of ethanol is 15430.22 g

Step-by-step explanation:

By using ideal gas equation

PV = nRT

Where P is pressure , R is gas constant

so, volume is

`V = (RT)/(P) = (8.314* (480+273))/(6000* 10^3)`

`V = 1.043 * 10^(-3) m^3/mol`

molar volume of vapor ethanol is

`V = 1.043 * 10^(-3) m^3/mol`

b)

volume of vessel is given
`0.35 m^3`

therefore total moles of ethanol in given vessel will be

`n =(V_(vessel))/(V)`

`n =(0.35)/(1.043*10^(-3))`

n = 335.44 mol

we know that

mole is given as [/tex]n = \frac{mass}{moleculae weight}[/tex]

weight of ethanol is 46 g/mol

n\times 46 = mass

`335.44* 46 = 15430.22 g`

mass of ethanol is 15430.22 g