Question

A lead atom has a mass of 3.14 x 10 to the negative 22nd g.How

many lead atoms are in a cube of lead that has a volume of 2.00cm
cubed, if the density of lead is 11.3 g/cm cubed?

Answer 1

Step-by-step explanation:

The given data is as follows.

Mass of a lead atom =
`3.14 * 10^(-22)`

Volume = 2.00
`cm^(3)`

Density = 11.3
`g/cm^(3)`

As it is mentioned that 1 cubic centimeter contains 11.3 grams of lead.

So, in 2 cubic centimeter there will be
`2 * 11.3 g = 22.6 g` of lead atoms.

One lead atom has a mass of
`3.14 * 10^(-22)`. Therefore, number of atoms present in 22.6 g of lead will be as follows.

`(22.6 g)/(3.14 * 10^(-22))`

=
`7.197 * 10^(22) atoms`

Thus, we can conclude that there are
`7.197 * 10^(22) atoms` of lead are present.