Question

Diameters of small commercially available steel rods vary by sixteenths of an inch. Select the required commercial size of the rod required to support a tensile load of 35,000 lb if the tensile stress cannot exceed 20,000 psi.

Answer 1

`1(1)/(2)` in dia rod

Step-by-step explanation:

Given;

Maximum tensile stress = 20,000 psi

Applied tensile load = 35,000 lb

Now,

the area of the steel rod required =
`\frac{\textup{Applied tensile load}}{\textup{Maximum tensile stress}}`

or

the area of the steel rod required =
`\frac{\textup{35,000}}{\textup{20,000}}`

or

the area of the steel rod required = 1.75 in²

Also, Area of rod =
`(\pi)/(4)d^2`

where, d is the diameter of the rod

1.75 in² =
`(\pi)/(4)d^2`

or

d = 1.49 in

So we can use
`1(1)/(2)` in dia rod