Answer: The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.
Explanation:
According to the dilution law,
where,
= molarity of stock
solution = 12.0 M
= volume of stock
solution = 5.0 ml
= molarity of dilute
solution = 0.2 M
= volume of dilute
solution = ?
Putting in the values we get:
Therefore, 300 ml of 0.2M HCl can be made from 5.0mL of a 12.0M
solution.