Question

A water quality standard recognized in British Columbia for Zn

in marine environments is 10 ?g/L. Convert this to (a) milligrams
per liter and (b) nanomoles per liter. Molecular weight of Zn:
63.38 g/mol.

Answer 1

`(a)\ 10^4\ mg/L`

`(b)\ 10^(10)\ mg/L`

Step-by-step explanation:

(a) As given in question,

concentration of zinc in atmosphere = 10 g/L

By converting g to mg,

1 g = 1000 mg

=> 10 g = 10 x 1000 mg

`=\ 10^4\ mg`

Hence, the concentration of zinc in the environment in mg/L is
`10^4\ mg/L.`

(a) As given in question,

concentration of zinc in atmosphere = 10 g/L

By converting g to nano gm,

`1\ g\ =\ 10^9\ nano\ gm`

`=>\ 10\ g\ =\ 10\ *\ 10^9\ nano\ gm`

`=\ 10^(10)\ nano\ gm`

Hence, the concentration of zinc in the environment in nano gm/L is
`10^(10)\ nano\ gm/L.`