Question

What is the silver concentration in a solution prepared by mixing 250

mL of 0.310 M silver nitrate with 100 mL of 0.160 M of sodium chromate?

Answer 1

0.221M

Step-by-step explanation:

From the question ,

The Molarity of AgNO₂ = 0.310 M

Hence , the concentration of Ag⁺ = 0.301 M

The volume of AgNO₂ = 250 mL

and,

The Molarity of Sodium chromate = 0.160 M

The volume of Sodium chromate = 100 mL.

As the solution is mixed the final volume becomes ,

250mL +100mL = 350mL

Now, using the formula , to find the final molarity of the mixture ,

M₁V₁ ( initial ) = M₂V₂ ( final )

substituting the values , in the above equation ,

0.310M * 250ml = M₂ * 350ml

M₂ = 0.221M

Hence , the concentration of the silver in the final solution = 0.221M