Answer:
4.53 second, 195 ft/s
Step-by-step explanation:
u = 50 ft/s
h = 555 ft
g = 32 ft/s^2
Let the time taken by the ball to reach the ground is t and the velocity of the ball as it hits the ground is v.
Use third equation of motion
![v^(2)=u^(2)+2as](https://img.qammunity.org/2020/formulas/physics/high-school/obiz6wq8wm4hlxtgrpgte68bf8o00xokbq.png)
![v^(2) = 50^(2)+2* 32 * 555](https://img.qammunity.org/2020/formulas/physics/high-school/umi0c0bo542wcxsgivk0l7v5a6vztzokhl.png)
v = 195 ft /s
Thus, the ball strikes the ground with velocity 195 ft/s.
Use first equation of motion
v = u + at
195 = 50 + 32 t
32 t = 145
t = 4.53 second
Thus, the ball reach the ground in 4.53 second.